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provide sufficient well supply to mee <br />provide storage based on 90% of th~ <br />hour period. The storage volume is <br />hour demand and the average suppl~ <br /> <br />A common historical formula for balancing well supply and water storage is to <br /> average demand on the maximum day and <br /> maximum day demand occurring during a <br /> ,ual to the volume necessaw to balance <br /> with provision of a 33% storage reserve. <br /> <br />For example, assume 3,35 mgd maxi <br /> <br />1) Well Supply <br /> 3.35 mgd + 24 hours = 140,0(:: <br /> <br />2) <br /> <br />~um day demand <br /> <br /> gal/hour <br />Provide sufficient well supply to meet average demand of 2333 gpm with any <br />one well out of service. ~ <br /> <br />Assume 90% of 3.5; mg in 16 hours = 3.0 mg <br />Assume 140,000 gal/hour from wells for 16 hours = 2,.24..mg <br /> Difference between 16 hour demand & supply = 0.76 mg <br /> Provide 33% storage reserve = 0.25. mg <br /> Total Storage = 1.0 mg <br /> <br />.tZ rd <br /> <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br /> <br /> I <br /> <br />Post-R" Fax Note 7671 Dale "1 # ot [~ '" <br />Fax ~ Fax # <br /> <br /> <br />